CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A slab of glass of thickness of 3 units and refractive index 3 is surrounded by vacuum and is placed as shown. A light ray is incident at the point (2,53) as shown. The point where the ray will cut the X axis is:

A
(6,0)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(5+3,0)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(9,0)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(8,0)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (9,0)
Given thickness of slab BC=3 units
coordinate of B is (2,53)
CE=53

Applying Snell's law at B,
1sin i=μsin r
1sin 60=3sin r 32=3sin r
r=30

From ΔBCD
CD=BCtanr=3tan 30=3
DE=CECD=[533]=43
From triangle DEF
EF=DEcot60=43cot 60=4
Coordinate of point E=(3+2+4,0)=(9,0)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Playing with Glass Slabs
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon