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Question

A slit of size $$0.15\ cm$$ is placed at $$2.1\ m$$ from a screen. On illuminated it by a light of wavelength $$5 \times 10^{-5}\ cm$$. The width of central maxima will be


A
70 mm
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B
0.14 mm
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C
1.4 mm
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D
0.14 cm
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Solution

The correct option is C $$1.4\ mm$$
Width of central maxima $$=\dfrac{2 \lambda D}{d}$$
$$=\dfrac{2 \times 2.1 \times 10^{-7}}{0.15 \times 10^{-2}}=1.4 \times 10^{-3}\ m=1.4\ mm$$

Physics

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