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Question

A slot of 25 mm × 25 min is to be milled in a workpiece of 300 mm length using a side and face milling cutter of diameter 100 mm, width 25 mm and having 20 teeth. For a depth of cut 5 mm, feed per tooth 0.1 mm, cutting speed 35 m/min and approach and over travel distance of 5 mm each, the time required for milling the slot is minute (round off to one decimal place).

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Solution

L = 300 mm, D = 100 mm, Z = 20 teeth,
d = 5 mm, f = 0.1 mm, V = 35 m/min
A = O = 5 mm
V=πDN

35=π×0.100×N

N=π×111.408rpm

t=L+D2+A+OfzN

=300+1002+5+50.1×20×111.408

=1.6157minperpass
For 25 mm cuts min 5 mm depth of cut 5 pass needed.
Total machining time = 5 × 1.6157

=8.078min8.1min


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