    Question

# A small circular loop of radius l=1 cm is kept inside a larger circular loop of radius r such that both are coplanar and concentric. If the current in larger loop is as shown in the graph, then current induced in the smaller loop any time is represented as In at any instant. Take anticlockwise current as positive. List -1 contains time instants, and List-2 contains the values for In. Match them. Take μ0π2Rr=1. List -1List -2(I)0 sec(p)25μA(II)13sec(Q)12.5μA(III)32sec(R)0μA(IV)53sec(S)−6.25μA(T)−12.5μA(U)−25μA

A
IP,IIR,IIIU,IVP
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B
IU,IIR,IIIP,IVU
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C
IP,IIR,IIIP,IVP
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D
IU,IIR,IIIU,IVU
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Solution

## The correct option is D I→U,II→R,III→U,IV→Uϕ=BA=μ0i2rπl2 ∈=dϕdt ⇒∈=μ0π2rl2(didt) In=∈R ⇒In=μ0π2rRl2(didt)=10−4(didt)=100(didt)μA at t=0,didt=11614=14⇒In=25μA clockwise So at t=0, In=−25μA at t=13sec, didt=0⇒In=0 at t=32sec, didt=14⇒In=25μA clockwise At t=32, In=−25μA at t=53sec, didt=14⇒In=25μA clockwise. ∴ At t=53, In=−25μA So, I→U,II→R,III→U,IV→U  Suggest Corrections  0      Related Videos   PHYSICS
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