A small indoor greenhouse is made entirely of glass panes held together with tape. It is $30 c m$ long, $25 c m$ wide and $25 c m$ high. How much of tape is needed for all the 12 edges?

$230 c m$

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$320 c m$

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$302 c m$

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$203 c m$

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Solution

The correct option is B
$320 c m$

Given,
Length, $l = 30 c m$

Breadth, $b = 25 c m$

Height, $h = 25 c m$

Length of the tape
$=$ sum of all the edges of the green house
$= 4 l + 4 b + 4 h$
$= (4 \times 30) + (4 \times 25) + (4 \times 25)$
$= 320 cm$

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Similar questions

A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is $30 c m$ long, $25 c m$ wide and $25 c m$ high.
(i) What is the area of the glass?
(ii) How much of tape is needed for all the $12$ edges?

Q. In Fig. 7, a small indoor green house is made entirely of glass panes (including base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. What is the area of the glass? How much tape is required for all the 12 edges?

Q. A small indoor greenhouse is made entirely of glass panes held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. How much tape is needed for all the 12 edges?

Q. A small indoor greenhouse is made entirely of glass panes held together with tape. It is

30 c m

long,

25 c m

wide and

25 c m

high. How much of tape is needed for all the 12 edges?

Q. A small indoor greenhouse is made entirely of glass panes held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. How much tape is needed for all the 12 edges?

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A small indoor greenhouse is made entirely of glass panes held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. How much of tape is needed for all the 12 edges?

The correct option is B 320 cm Given, Length, l=30 cm Breadth, b=25 cm Height, h=25 cm Length of the tape = sum of all the edges of the green house =4l+4b+4h =(4×30)+(4×25)+(4×25) =320 cm

A small indoor greenhouse is made entirely of glass panes held together with tape. It is $30 c m$ long, $25 c m$ wide and $25 c m$ high. How much of tape is needed for all the 12 edges?

The correct option is B
$320 c m$

Given,
Length, $l = 30 c m$

Breadth, $b = 25 c m$

Height, $h = 25 c m$

Length of the tape
$=$ sum of all the edges of the green house
$= 4 l + 4 b + 4 h$
$= (4 \times 30) + (4 \times 25) + (4 \times 25)$
$= 320 cm$