A small indoor greenhouse is made entirely of glass panes held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. How much tape is needed for all the 12 edges?

230 cm

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320 cm

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302 cm

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203 cm

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Solution

The correct option is B 320 cm
Given,
Length = 30 cm
Breadth = 25 cm
Height = 25 cm

Length of tape required = Total length of the edges of the cuboidal greenhouse
$= (4 l + 4 b + 4 h) c m$
$= (4 \times 30 + 4 \times 25 + 4 \times 25) c m$
$= 320 c m$

$∴$ Total length of tape required is 320 cm.

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Similar questions

Q. A small indoor greenhouse is made entirely of glass panes held together with tape. It is

30 c m

long,

25 c m

wide and

25 c m

high. How much of tape is needed for all the 12 edges?

Q. Question 6 (ii)
A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30cm long, 25 cm wide and 25 cm high.
(ii) How much of tape is needed for all the 12 edges?

Q. Question 6 (ii)
A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30cm long, 25 cm wide and 25 cm high.
(ii) How much of tape is needed for all the 12 edges?

Q. A small indoor greenhouse is made entirely of glass panes held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. How much tape is needed for all the 12 edges?

A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is $30 c m$ long, $25 c m$ wide and $25 c m$ high.
(i) What is the area of the glass?
(ii) How much of tape is needed for all the $12$ edges?

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A small indoor greenhouse is made entirely of glass panes held together with tape. It is 30 cm long, 25 cm wide and 25 cm high. How much tape is needed for all the 12 edges?

The correct option is B 320 cmGiven, Length = 30 cm Breadth = 25 cm Height = 25 cm Length of tape required = Total length of the edges of the cuboidal greenhouse =(4l+4b+4h) cm =(4×30+4×25+4×25) cm =320 cm ∴ Total length of tape required is 320 cm.

The correct option is B 320 cm
Given,
Length = 30 cm
Breadth = 25 cm
Height = 25 cm

Length of tape required = Total length of the edges of the cuboidal greenhouse
$= (4 l + 4 b + 4 h) c m$
$= (4 \times 30 + 4 \times 25 + 4 \times 25) c m$
$= 320 c m$

$∴$ Total length of tape required is 320 cm.