Question

# A sodium street light gives off yellow light that has a wavelength of 600 nm. Then (For energy of a photon take E = 12400 eV ∘Aλ( ∘A)

A
Frequency of this light is 7×1014 s1
B
Frequency of this light is 5×1014 s1
C
Wavenumber of this light is 3×106 m1
D
Energy of the photon is approximaltely 2.07 eV

Solution

## The correct options are B Frequency of this light is 5×1014 s−1 D Energy of the photon is approximaltely 2.07 eVGiven: wavelength = 600 nm = 600×10−9 m = 6000  ∘A We know, ν=cλ where c = speed of light  ν = frequency of the light λ = wavelength of the radiation So, ν = 3×108600×10−9 = 5×1014 s−1 E = 12400 eV ∘A6000 ∘A E = 2.07 eV

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