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Question

A sodium street light gives off yellow light that has a wavelength of 600 nm. Then
(For energy of a photon take E = 12400 eV Aλ( A)


Your Answer
A
Frequency of this light is 7×1014 s1
Correct Answer
B
Frequency of this light is 5×1014 s1
Your Answer
C
Wavenumber of this light is 3×106 m1
Correct Answer
D
Energy of the photon is approximaltely 2.07 eV

Solution

The correct options are
B Frequency of this light is 5×1014 s1
D Energy of the photon is approximaltely 2.07 eV
Given: wavelength = 600 nm = 600×109 m = 6000  A
We know, ν=cλ
where c = speed of light 
ν = frequency of the light
λ = wavelength of the radiation
So, ν = 3×108600×109 = 5×1014 s1
E = 12400 eV A6000 A

E = 2.07 eV
 

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