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Question

A soft drink is available in two packs−
(i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm
(ii) a plastic cylinder with a circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

[Assume π=227]


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Solution

The tin can will be cuboidal in shape while the plastic cylinder will be cylindrical in shape.

Length (l) of the tin can = 5 cm

Breadth (b) of the tin can = 4 cm

Height (h) of the tin can = 15 cm
Capacity of the tin can =l×b×h=(5×4×15)cm3

=300 cm3

Radius (r) of the circular end of plastic cylinder =(72)cm=3.5 cm

Height (H) of the plastic cylinder = 10 cm
Capacity of the plastic cylinder =πr2H

=[227×(3.5)2×10]cm3=(11×35)cm3=385 cm3

Therefore, plastic cylinder has the greater capacity.

Difference in the capacity =(385300)cm3=85 cm3


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