Question

A soft drink is available in two packs-(i) a tin can with a rectangular base of length $5cm$ and width $4cm$, having a height of $15cm$ and (ii) a plastic cylinder with circular base of diameter $7cm$ and height $10cm$. which container has greater capacity and by how much?

• A. Cylinder has $85{cm}^3$greater capacity
• B. Tin has $85{cm}^3$greater capacity
• C. Cylinder has $65{cm}^3$greater capacity
• D. Tin has $65{cm}^3$greater capacity

Answer 1

The correct option is A Cylinder has $85{cm}^3$greater capacity

Volume of a cuboid $=l\times b\times h$
So, the volume of the cuboidal tin pack $=5\times 4\times 15=300{cm}^3$
Volume of a Cylinder $=\pi R^{2}h$
Radius of the cylindrical pack $=\frac{7}{2}cm$

Hence, volume of the cylindrical pack $=\frac{22}{7}\times \frac{7}{2}\times \frac{7}{2}\times 10=385{cm}^3$

Hence, the cylindrical pack has greater capacity than the cuboidal tin by $385-300=85{cm}^3$