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Question

A solid AB has a NaCl structure where B ions occupy the corners of the unit cell. If all the face centred atoms along one axis are removed then the resultant stoichiometry of the solid is:


A
AB2
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B
A2B
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C
A3B3
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D
A3B4
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Solution

The correct option is D A3B3
B ions are present at corners and face centres, and A+ ions are in the octahedral voids, i.e., at the edge centres and the body centre. A unit cell will contain 4A+ and 4B ions. In this, one axis removed, which means that two face centred ions and the body centred ion is removed. B lies on the face centres and A+ is at the body centre.
Contribution of two face centred B ions =2×12=1
In the resultant unit cell;
A+ ions present per unit cell = 4 - 1 = 3
B ions present per unit cell = 4 - 1 = 3
Stoichiometry = A3B3

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