Question

A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion $\left(Y^{–}\right)$ will be :

• A. 275.1 pm
• B. 322.5 pm
• C. 241.5 pm
• D. 165.7 pm

Answer 1

The correct option is C 241.5 pm

Given, radius of the cation is 100 pm .

As we know :

$\frac{r^{+}}{r^{-}}=0.414$ for NaCl

Substituting value of $r^{+}$ in above equation , we get

$r^{-}=\frac{100}{0.414}$

$\therefore r^{-}=241.5pm$

Hence, option C is correct .