Question

# A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion $$(Y^{–})$$ will be :

A
275.1 pm
B
322.5 pm
C
241.5 pm
D
165.7 pm

Solution

## The correct option is C 241.5 pmGiven, radius of the cation is 100 pm .As we know :$$\frac{r^+}{r^-}=0.414$$ for NaClSubstituting value of $$r^+$$ in above equation , we get $$r^-=\frac{100}{0.414}$$$$\therefore\ r^-=241.5\ pm$$Hence, option C is correct .Chemistry

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