Question

# A solid consisting of right circular cylinder with a hemisphere of one end and a cone and the other. Their common radius is 7 cm. The height of cylinder and cone are each of 4 cm. Find the volume of the solid.

Solution

## REF.ImageGiven,height of cylinder = height of cone = $$4 cm$$radius of all = $$7 cm$$To find : volume of the figureTh collective volume = volume of hemisphere + volume of cylinder + volume of cone$$\Rightarrow volume = (2/3\pi r^{3}+\pi r^{2}h+\dfrac{1}{3}\pi r^{2}h)unit^{3}$$$$= 2/3\pi (7^{3})+\pi (7^{2})4+\dfrac{1}{3}\pi (7^{2})4cm^{3}$$$$= 49\pi (14/3+4+4/3) cm^{3}= 49\pi (\dfrac{14+12+4}{3})$$$$= 490\pi cm^{3}$$$$= 490\times 22/7 cm^{3}= 1540 cm^{3}$$Mathematics

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