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Question

A solid consisting of right circular cylinder with a hemisphere of one end and a cone and the other. Their common radius is 7 cm. The height of cylinder and cone are each of 4 cm. Find the volume of the solid.


Solution

REF.Image
Given,
height of cylinder = height of cone = $$4 cm$$
radius of all = $$7 cm$$
To find : volume of the figure
Th collective volume = volume of hemisphere + volume of cylinder + volume of cone
$$\Rightarrow volume = (2/3\pi r^{3}+\pi r^{2}h+\dfrac{1}{3}\pi r^{2}h)unit^{3}$$
$$= 2/3\pi (7^{3})+\pi (7^{2})4+\dfrac{1}{3}\pi (7^{2})4cm^{3}$$
$$= 49\pi (14/3+4+4/3) cm^{3}= 49\pi (\dfrac{14+12+4}{3})$$
$$= 490\pi cm^{3}$$
$$= 490\times 22/7 cm^{3}= 1540 cm^{3}$$

1371018_1227341_ans_b88960044ccf4a0fba47b86979b49e62.JPG

Mathematics

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