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Question

A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. (Use π = 3.14)

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Solution

Height (h1) of larger cylinder =220 cm
Radius (r1) of larger cylinder = 242=12 cm
Height (h2) of smaller cylinder = 60 cm
Radius (r2) of smaller cylinder =8 cm
Total volume of pole = Volume of larger cylinder + Volume of smaller cylinder

=πr21h1+πr22h2

=(π(12)2×220)+(π(8)2×60)

=π[144×220+64×60]

=3.14[31,680+3,840]

=3.14×35520=111,532.8 cm 3

Mass of 1 cm3 iron = 8 g

Mass of 111532.8 cm 3 iron = 11532.8×8=892262.4 g

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