CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A solid sphere of mass M and radius R is divided into two unequal parts. The first part has a mass of 7M8 and is converted into a uniform disc of radius 2R. The second part is converted into a uniform solid sphere. Let I1 be the moment of inertia of the disc about its axis and I2 be the moment of inertia of the new sphere about its axis. The ratio I1I2 is given by


Solution

The given situation is shown in the figure given below

Density of given sphere of radius R is
ρ=MV=M43πR3
Let radius of sphere formed from second part is r, then 
mass of second part = V×ρ
18M=43πr3×M43πR3
r3=R38r=R2
Now, I1= moment of inertia of disc (radius is 2R)
=Mass×R22=78M×(2R)22=74MR2
and I2 = moment of inertia of sphere
(radiusR2and mass18M)about its axis=25×Mass×(Radius)2
=25×18M×(R2)2=MR280
I1I2=74MR2180MR2=140

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image