Question

# A solid weighs $$32\ gf$$ in air and $$28.8\ gf$$ in water. Find: $$R.D.$$ of solid.

Solution

## Weight of the solid in air, $$W_1=32\ gf$$weight of the solid immersed completely in water, $$W_2=28.8\ gf$$density of the liquid $$=0.9\ gcm^{-3}$$To find the R.D. of the solidRelative density of the solid $$=\dfrac{W_1}{W_3-W_2}\times$$ relative density of water$$=\dfrac{32}{32-28.8}\times 1=10$$Physics

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