A solid weighs 50 N in the air and 45 N when completely immersed in water- Density of water -1000 kg - m 3- Calculate the volume of the solid- Take acceleration due to gravity -10 m - s 2 A- 5 m 3B- 5 - 10-6 m 3C- 500 m 3D- 5 - 10-3 m 3

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Buoyant Force

A solid weigh...

Question

A solid weighs $50 N$ in the air and $45 N$ when completely immersed in water. Density of water $ρ$ = $1000 k g / m^{3}$ . Calculate the volume of the solid.

(Take acceleration due to gravity = $10 m / s^{2}$ )

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Solution

The correct option is D
Weight of solid in air = $50 N$
Weight of solid in water = $45 N$
Buoyant force = Weight of water displaced = $50 N - 45 N = 5 N$
Density of water $ρ$ = $1000 k g / m^{3}$

Acceleration due to gravity = $10 m / s^{2}$

Volume of solid = $v_{s}$

Buoyant force = $v_{s} ρ g$

Volume of solid $v_{s}$ = $\frac{5 N}{1000 k g / m^{3} \times 10 m / s^{2}}$ = $5 \times 10^{- 4} m^{3}$

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A solid weighs 50 N in the air and 45 N when completely immersed in water. Density of water ρ = 1000 kg/m3. Calculate the volume of the solid. (Take acceleration due to gravity = 10 m/s2)

A solid weighs $50 N$ in the air and $45 N$ when completely immersed in water. Density of water $ρ$ = $1000 k g / m^{3}$ . Calculate the volume of the solid.

(Take acceleration due to gravity = $10 m / s^{2}$ )