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Question

A solution contain 25%water,25%ethanol and 50%acetic acid by mass.calculate the mole fraction of each component.


Solution

For simplicity take: 25g H2O . 25g ethanol and 50g CH3COOH 

Calculate mol of each: 
molar mass H2O = 18g/mol 
25g = 25/18 = 1.39 mol 

Molar mass ethanol CH3CH2OH = 46g/mol 
25g = 25/46 = 0.543 mol 

Molar mass CH3COOH = 60g/mol 
50g = 50/60 = 0.833 mol 

Total mol = 1.39+0.543 +0.833 = 2.766 mol 

Mol fraction H2O = 1.39/2.766 = 0.503 
Mol fraction CH3CH2OH = 0.196 
Mol fraction CH3COOH = 0.833/2.766 0.301

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