A solution of 1.25 g of a non-electrolyte in 20 g of water freezes at 271.94 K. If Kf = 1.86 K/molality then the molecular wt. of the solute is : (1) 90.1 g/mol (2) 90.5 g/mol (3) 92.4 g/mol (4) 96.01 g/mol

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Q. A solution of 1.25 g of a non - electrolyte in 20 g of water freezes at 271.94 K. If

K_{f}

= 1.86 K molality -1 then the molecular wt. of the solute is

A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If K_f = 1.86 K kg mol^-1,then the molecular weight of the solute will be:

A solution of 1.25g of non - electrolyte in 20g of water freezes at 271.94 K. If K_f = 1.86 K kg mol^-1, then the molecular weight of the solute will be:

Q. A solution of

1.25

g of a certain non-volatile substance in

20

g of water freezes at

271.94

K. Calculate the molecular mass of the solute

(K_{f} = 1.86 K . k g . m o l^{- 1})

Q. Molal depression constant for water is

1.86 K k g . {m o l}^{- 1}

. The freezing point of a

0.05

molal solution of a non-electrolyte in water is:

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