Question

A solution of $9.65A$ flowing for $10min$ deposits $3.0g$ of the metal which is monovalent. The atomic mass of the metal is :

• A. $10$
• B. $50$
• C. $30$
• D. $96.5$

Answer 1

The correct option is B $50$

Let A be the atomic weight of metal.

1 mol of metal = $Ag$ $96500C$

$\Rightarrow$ A g

$9.65\times 10\times 60\Rightarrow \frac{A}{96500}\times 9.65\times 10\times 60$

$\therefore A\times 0.06$ = 3 g

$A=\frac{3}{0.06}$

= $50$