Question

A solution of copper sulphate electrolysed for $20$ minute with a current of $1.5$ Ampere. Calculate the mass of copper deposited at the cathode. $(F=96500C)$

Answer 1

We know that,

$W=\frac{EIt}{F}$

$=\frac{63.52\times 1.5\times 20\times 60}{2\times 96500}=0.529g$