Question

'$A$' solution of strong acid/strong base of $pH=x$ is mixed with equal volume of '$B$' solution of strong acid/strong base of $pH=(14-x)$, such that the resulting mixture has a $pH=7$. If only natural number values of $x$ are allowed, excluding $x=7$, then how many possible values of $x$ would be there? (Negative values of $pH$ are not to be considered)

Answer 1

$p{H}_1=x$

$\left[H^{+}\right]={10}^{-x}$

$pO{H}_1=14-x$

$\left[O{H}^{-}\right]={10}^{x-14}$

$p{H}_2=14-x$

$\left[H^{+}\right]={10}^{x-14}$

$pO{H}_2=14-(14-x)=x$

$\left[O{H}^{-}\right]={10}^{-x}$

$\left[H^{+}\right]=\left[O{H}^{-}\right]$

So, it's neutral

$pH=7$

$x=1,2,3,4,5,6,8,9,10,11,12,13,14,0$

$14$ possible values.