    Question

# A sound wave of wavelength 50 cm travels in a gas medium. If the difference between the maximum and minimum pressures at a given point is 5×10−3 N/m2 and the amplitude of vibration of the particles of the medium is 5×10−10 m, find bulk modulus of the medium.

A
105 N/m2
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B
2×105 N/m2
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C
3×105 N/m2
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D
4×105 N/m2
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Solution

## The correct option is D 4×105 N/m2Given that, Wavelength, λ=50 cm Displacement amplitude, S0=5×10−10 m Pressure amplitude P0=BkS0 where B is bulk modulus of the medium and k is wave number. P0=Pmax−Pmin2 =5×10−32 =2.5×10−3 N/m2. k=2πλ=2π0.5=4π Hence, B=P0kS0 =2.5×10−34×3.14×5×10−10 =3.98×105 N/m2 ≈4×105 N/m2  Suggest Corrections  0      Similar questions
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