A source of light having wavelength $λ$ ejects photo electron with maximum kinetic energy $1 e V$ . On irradiating same metal with wavelength $1 / 3$ , the eject photoelectron posses kinetic energy of $4 e V$ . The work function of metal is :

2 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.5 e V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.5 e V$
Let the work function of the metal be $A$
Thus, energy irradiated=work function + Kinetic energy
Given: $h c / λ = A + 1 e V$
and $3 h c / λ = A + 4 e V$
From above two relations:
$3 A + 3 e V = A + 4 e V$
$2 A = 1 e V$
$A = 0.5 e V$
option D is correct

Suggest Corrections

Similar questions

A light source of wavelenght $^{'} λ^{'}$ illuminates on a metal surface, a photoelectron of Kinetic energy $1 e V$ is emitted. The another light source of wavelength $\frac{λ}{3}$ ejects photo electron from the same metal surface with Kinetic energy is $4 e V$ , the value of work function is