CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A 40mm long spring is stretched by applying a force. If 10N force is required to stretch the spring through one mm, then work done in stretching the spring through 40mm is:


Open in App
Solution

Step 1: Given data

Length of the spring (L) = 40mm

Force (F) applied to stretch the spring by one mm (0.001m) = 10N

Step 2: Formula used

  1. F=kx, where F is the force applied to stretch the spring, k is the spring constant and x is the displacement.
  2. W=12kx2, where W is the work done to deform the spring.

Step 3: Find the spring constant

Hooke's law states that:

F=kx

On substituting the given values in the formula, we get:

10=k×10-3k=104N/m

Step 4: Calculate work done

The formula for work done in stretching a spring is:

W=12kx2

It is given that x=40mm=0.04m.

On substituting the given values in the formula, we get:

W=12×104×0.042W=8J

Thus, the work done in stretching the spring through 40mm is 8J.


flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image