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Question

A spring of force constant 800 N/m has an extension of 5 cm. Find work done in extending it from 5 cm to 15 cm.

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Solution

Step 1: Expression for Work done by spring
Work done in stretching spring from length x1 to x2 is given by:
W=12k(x22x21)
Where k is the spring constant

Step 2: Calculations
Putting given values, we get:
W=12×800N/m[(0.15m)2(0.05m)2]
=8 J

Hence the work done in extending the spring from 5cm to 15cm is 8 J.

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