Question

# A spring of force constant $$800$$ N/m has an extension of $$5$$ cm. Find work done in extending it from $$5$$ cm to $$15$$ cm.

Solution

## $$\textbf{Step 1: Expression for Work done by spring}$$ Work done in stretching spring from length $$x_{1}$$ to  $$x_{2}$$ is given by:                        $$W = \dfrac{1}{2} k (x_{2}^{2} - x^{2}_{1})$$ Where $$k$$ is the spring constant$$\textbf{Step 2: Calculations}$$ Putting given values, we get:                       $$W = \dfrac{1}{2} \times 800N/m [(0.15m)^{2} - (0.05m)^{2}]$$                              $$= 8\ J$$ Hence the work done in extending the spring from $$5cm$$ to $$15cm$$  is $$8\ J.$$ Physics

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