Question

# A spy report about a suspected car reads as follows. "The car moved $2.00km$ towards the east, made a perpendicular left turn, ran for $500m,$ made a perpendicular right turn, ran for $4.00km$ and stopped". Find the displacement of the car.

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Solution

## Consider East direction is indicated as $i$ west direction is indicated as $-i$ North direction is indicated as $j$ South direction is indicated as $-j$ Motion initially $2km$ towards the east $=2i$ ,Then left turn means north and $0.5km=0.5j$Then a right turn means east and $4.0km=4j$ Net displacement will be $\sqrt{{6}^{2}+{\left(0.5\right)}^{2}}=6.02Kms$$2i+0.5j+4i=6i+0.5j$

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