A square and a rectangle has similar area. If the length of the rectangle is $16 c m$ and the side of the square is $8 c m$ , what is the breadth of the rectangle ?

3 c m

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4 c m

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5 c m

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6 c m

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Solution

The correct option is B $4 c m$
Given:
For rectangle, length = $16 c m$
For square, side = $8 c m .$
It is given that area of rectangle = area of square
$\Rightarrow l e n g t h \times b r e a d t h = s i d e^{2}$
$\Rightarrow 16 \times b r e a d t h = 8^{2} = 64$
$\Rightarrow b r e a d t h = \frac{64}{16} = 4 c m .$

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A square and a rectangle has similar area. If the length of the rectangle is 16 cm and the side of the square is 8 cm, what is the breadth of the rectangle ?

The correct option is B 4 cmGiven: For rectangle, length = 16 cm For square, side = 8 cm. It is given that area of rectangle = area of square ⇒length×breadth=side2 ⇒16×breadth=82=64 ⇒breadth=6416=4 cm.

A square and a rectangle has similar area. If the length of the rectangle is $16 c m$ and the side of the square is $8 c m$ , what is the breadth of the rectangle ?