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Question

A square has one vertex at the vertex of the parabola y2=4ax and the diagonal through the vertex lies along the axis of the parabola. If the ends of the other diagonal lie on the parabola, the coordinates of the vertices of the square are

A
(4a,4a)
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B
(4a,4a)
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C
(0,0)
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D
(8a,0)
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Solution

The correct options are
A (0,0)
B (4a,4a)
C (4a,4a)
D (8a,0)
AC is one diagonal along x -axis, then the other diagonal is BD where both B and D lie on parabola.
Also slope of AB is tanπ4=1.
If B is (at2,2at) then the slope of AB
=2atat2=2t=1
t=2
Therefore, B is (4a,4a) and hence D is (4a,4a)
Clearly, C is (8a,0).

1634151_1768137_ans_bac563bca0f041c9816424c536f04de9.png

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