Question

A square is inscribed in the circle $x^2+y^2-2x+4y+3=0,$ whose sides are parallel to the coordinate axes. One vertex of the square is

• A. $(1+\sqrt{2},-2)$
• B. $(1-\sqrt{2},-2)$
• C. $(1-2+\sqrt{2})$
• D. None of these

Answer 1

The correct option is D None of these

We can see that the centre of the given circle is (1, -2).
Since the sides of square are parallel to the axes, therefore, first three alternates cannot be vertices of square because in first two (a and b) y = -2 and in (c) (x = 1), which passes through centre (1, -2) but it is not possible.
Therefore none of the above three is correct.