A square lawn has a circular pond in the centre. Find the shaded region's area given that the diameter of circle is $\frac{1}{3}$ times the diagonal of square with sides 3 cm.

\frac{9 - π}{2}

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\frac{(18 - π)}{4}

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\frac{(18 - π)}{18}

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\frac{(2 + π)}{8}

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Solution

The correct option is B $\frac{(18 - π)}{4}$
Diagonal of Square $= 3 \sqrt{2}$
Diameter of Circle $= \sqrt{2}$
Required Area $= \frac{A r e a o f S q u a r e - A r e a o f C i r c l e}{2}$
$= \frac{9 - \frac{π}{2}}{2} = \frac{18 - π}{4}$

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A square lawn has a circular pond in the centre. Find the shaded region's area given that the diameter of circle is 13 times the diagonal of square with sides 3 cm.

The correct option is B (18−π)4Diagonal of Square =3√2 Diameter of Circle =√2 Required Area =Area of Square−Area of Circle2 =9−π22=18−π4

A square lawn has a circular pond in the centre. Find the shaded region's area given that the diameter of circle is $\frac{1}{3}$ times the diagonal of square with sides 3 cm.

The correct option is B $\frac{(18 - π)}{4}$
Diagonal of Square $= 3 \sqrt{2}$
Diameter of Circle $= \sqrt{2}$
Required Area $= \frac{A r e a o f S q u a r e - A r e a o f C i r c l e}{2}$
$= \frac{9 - \frac{π}{2}}{2} = \frac{18 - π}{4}$