Question

A starts driving from P to Q at 9 am and B starts driving from Q to P at 10 am. B is 50% faster than A. What is the time when they meet if P and Q are 300 km apart and A's speed is 50 km/h?

• A. 12:30 pm
• B. 12 noon
• C. 11:00 am
• D. 11:30 am

Answer 1

The correct option is B 12 noon

A's speed is 50 km/h and B's speed will be 75 km/h.
Since A starts at 9 am, the distance travelled by A till 10 am = 50 km
Relative speed after 10 am = 50 + 75 = 125 km/h
Now, distance between them at 10 am = 300 - 50 = 250 km
Time $=\frac{250}{125}=2h$
Thus, they will meet at 12 noon.