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Question

A stationary bomb explodes into three pieces. One piece of 2 Kg mass moves with a velocity of 8ms1 at right angles to the other pieces of mass 1 kg moving with a velocity of 12ms1. If the mass of the third piece is 0.5 kg, then its velocity is

A
10ms1
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B
20ms1
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C
30ms1
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D
40ms1
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Solution

The correct option is D 40ms1
Stationary so initial momentum will be zero.
momentum of 2kg is P1=2×8=16kgm/s
that if 1kg is P2=1×12=12kgm/s
both being at right angle so their resultant will be P=P21+P22=256+144=20kgm/s
the third should have same momentum but in opposite direction to make the net momentum zero.
Now its velocity should be V=Pm=200.5=40m/s

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