Question

# A steel flat plate of a rectangular section of size 70mm×8mm is connected to a gusset plate by three bolts each having a shear capacity of 30kN. If allowable tensile stress in flat is 160Mpa, the maximum tension that can be applied to flat plate is :

A
110kN
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B
75kN
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C
85kN
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D
90kN
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Solution

## The correct option is B 75kNNet area calculationAlong 1−2−3−4−6, A1=(70−3×10+2×3024×20)×8 =500mm2 Along 1−2−3−5, A2=(70−2×10+3024×20)×8 =490mm2 Along 7−3−5, A3=(70−10)×8 =480mm2 ∴ Effective net area, An=480mm2 Strength of flat in net area rupture =An×160N/mm2 =480×160×10−3kN =76.8kN Strength of bolts =30×3=90kN ∴ Maximum load that can be applied =Min(76.8,90) =76.8kN

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