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Question

A steel meter scale is to be ruled so that millimeter intervals are accurate within about 5×105 mm at a certain temperature. The maximum temperature variation allowable during the ruling is (Coefficient of linear expansion of steel=10×106 K1)

A
2 C
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B
5 C
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C
7 C
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D
10 C
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Solution

The correct option is B 5 C
In this case, change in length is allowed to be 5×105 mm
Length of 1 division =1 mm
α=10×106dt
putting all the values we get value of maximum temperature variation (dt) as 50C

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