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Question

A steel rod of length 1 m is heated from 25C to 75C keeping its length constant. The longitudinal strain developed in the rod is (Given: Coefficient of linear expansion of steel =12×106/C) n×104 . Report n. 


Solution

Strain developed:
=αΔT=(12×106)(50)=6×104
Strain will be negative, as the rod is in a compressed state.   
Why this question?

Strain without changing length- yes that happens!

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