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Question

A steel wire of cross-sectional area 0.5 mm2 is held between two fixed supports. If the wire is just taut at 20°C, determine the tension when the temperature falls to 0°C. Coefficient of linear expansion of steel is 1.2 × 10–5 °C–1 and its Young's modulus is 2.0 × 10–11 Nm–2.

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Solution

Given:
Cross-sectional area of the steel wire, A = 0.5 mm2 = 0.5 × 10–6 m2
The wire is taut at a temperature, T1 = 20 °C,
After this, the temperature is reduced to T2 = 0 °C
​So, the change in temperature, Δθ = T1-T2 = 20 °C
Coefficient of linear expansion of steel, α = 1.2 ×10–5 °C​-1
Young's modulus, γ = 2 ×1011 Nm​-2
Let L be the initial length of the steel wire and L' be the length of the steel wire when temperature is reduced to 0°C.
Decrease in length due to compression, ΔL = L'-L= LαΔθ ...(1)
Let the tension applied be F.

γ=stressstrain=FAΔLLγ=FA×LΔLΔL=FLAY ...(2)
Change in length due to tension produced is given by (1) and (2).
So, on equating (1) and (2), we get:
LαΔθ=FLAYF=αΔ θAY =1.2×10-5×20-0×0.5×10-6×2×1011 =1.2×20F=24 N
Therefore, the tension produced when the temperature falls to 0°C is 24 N.

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