A steel wire of length $4 m$ is stretched by a force of $100 N$ . The work done to increase the length of the wire by $2 m m$ is

0.4 J

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0.2 J

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0.1 J

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1 J

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Solution

The correct option is A $0.1 J$
$Work done = \frac{A Y}{2 L} l^{2}$ (using standard result $Y = \frac{(\frac{F}{A})}{(\frac{change in length}{actual length})}$ )
$= \frac{F l}{2} (∵ F = \frac{A Y l}{L})$
$= \frac{100 \times 2}{2 \times 1000}$
$= 0.1 J$

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A steel wire of length 4m is stretched by a force of 100N. The work done to increase the length of the wire by 2mm is

The correct option is A 0.1J Work done=AY2Ll2 (using standard result Y=(FA)(change in lengthactual length))=Fl2(∵F=AYlL)=100×22×1000=0.1J

A steel wire of length $4 m$ is stretched by a force of $100 N$ . The work done to increase the length of the wire by $2 m m$ is

The correct option is A $0.1 J$
$Work done = \frac{A Y}{2 L} l^{2}$ (using standard result $Y = \frac{(\frac{F}{A})}{(\frac{change in length}{actual length})}$ )
$= \frac{F l}{2} (∵ F = \frac{A Y l}{L})$
$= \frac{100 \times 2}{2 \times 1000}$
$= 0.1 J$