A steel wire of original length 1 m and cross-sectional area 4.00 mm2 is clamped at the two ends so that it lies horizontally and without tension. If a load of 2:16 kg is suspended from the middle point of the wire, what would be its vertical depression?

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A steel wire of original length 1 m and cross-sectional area $4.00 m m^{2}$ is clamped at the two ends so that it lies horizontally and without tension. If a load of 2.16 kg is suspended from the middle point of the wire, what would be its vertical depression ?

Y of the steel = $2.0 \times 10^{11} N m^{- 2} . T a k e g = 10 m s^{- 2}$ .

Q. A wire of length

L

is clamped at two ends so that it lies horizontally and without tension. A weight

W

is suspended from the middle point of the wire. The vertical depression is _______. (Young's modulus is

Y

Q. A mild steel wire of length 1.0 m and cross-sectional area 0.50 × 10¯² cm² is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid-point of the wire. Calculate the depression at the midpoint.

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