A stone dropped from the top of a tower to travel (5/9) of the height of the tower during the last second of its fall.The time of fall is??

Open in App

Solution

Suggest Corrections

Similar questions

Q. A stone dropped from the top of a tower travels

\frac{5}{9}

th of the height of tower during the last second of fall. Height of the tower is: (take g =

10 m / s^{2}

)

Q. A stone dropped from the top of a tower covers

24.5

m in the last second of its fall. Height of the tower is

A body is dropped from the top of a tower. During the last second of its fall, it covers 16/25th of the height of the tower. Calculate the height of the tower.

A body dropped from top of a tower fall through $40 m$ during the last two seconds of its fall. The height of the tower is
( $g = 10 {m/s}^{2}$ )

Q. A body dropped from the top of a tower falls through

40 m

during the last two seconds of its fall. The height of tower is

(g = 10 m / s^{2})

Join BYJU'S Learning Program

Select...