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Question

A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 second, the next 5s and next 5 second respectively. The relation between h1, h2 and h3 is :

A
h1=2h2=3h3
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B
h1=h23=h35
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C
h2=3h1 and h3=3h2
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D
h1=h2=h3
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Solution

The correct option is B h1=h23=h35
Given, u=0
We will use equation of motion:
s=ut+12gt2
and, v=u+at
In the first 5sec, height covered will be:
h1=0+12g(5)2
h1=125m
after first 5sec, the velocity will be:
v1=0+g(5)=50m/s
and, in the next five seconds, height covered will be:
h2=50(5)+12g(5)2=375m
and velocity is, v2=v1+gt,
v2=50+g(5)=100m/s.
so, in next 5sec, height covered will be:
h3=100(5)+12g(5)2=500+125
h3=625m
so, h1=h23=h35
So, the correct option is (B)


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