A stone is projected from the ground with a velocity of 14m/s one second later it clears a wall 2m high. The angle of projection is (g=10m/s2)

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Q. A stone is projected the ground with velocity 25 m/s. Two seconds later, it just clears a wall 5 m high. The angle of projection of the stone is

(g = 10 m / {s e c}^{2})

A stone is projected from the ground with velocity 25 m/s. Two seconds later, it just clears a wall 5 m high. The angle of projection of the stone is $(g = 10 m / s e c^{2})$

Q. A stone is projected from the ground with a velocity of

25 m / s

2

seconds later, it just clears wall

5 m

high. Then angle of projection of the stone and the greatest height reached are-

[

Neglect air resistance, Assume

g = 10 m / s e c^{2}

]

Q. A stone is projected from the ground with a velocity of

14 m s^{- 1}

one second later it clean a wall

2 m

high. The angle of projection is

(g = 10 m s^{- 2})

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