1
Question
A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
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Solution
Given data:
Initial velocity
u = 0
Tower height = total distance = 19.6m
g = 9.8 m/s2
Consider third equation of motion
v2 = u2 + 2gs
v2 = 0 + 2 × 9.8 × 19.6
v2 = 384.16
v = √(384.16)
v = 19.6m/s
Given data:
Initial velocity
u = 0
Tower height = total distance = 19.6m
g = 9.8 m/s2
Consider third equation of motion
v2 = u2 + 2gs
v2 = 0 + 2 × 9.8 × 19.6
v2 = 384.16
v = √(384.16)
v = 19.6m/s
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