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Question

A stone is thrown at an angle θ to the horizontal reaches a maximum height H, then the time of flight of stone will be
  1. 22Hg
  2. 2Hg
  3. 22H sinθg
  4. 2H sinθg


Solution

The correct option is A 22Hg
We know that,
Maximum height,H=u2sin2θ2gand Time of flight,T=2u sin θgT2=4u2sin2θg2
T2H=8gT=8Hg=22Hg

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