Question

A stone is thrown at an angle $\theta$ to the horizontal reaches a maximum height H. Then the time of flight of stone will be

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

H = $\frac{u^2{sin}^2\theta }{2g}$ and T = $\frac{2usin\theta }{g}$ $\Rightarrow$ $T^2$ = $\frac{4u^2{sin}^2\theta }{g^2}$
$\therefore$ $\frac{T^2}{H}$ = $\frac{8}{g}$ $\Rightarrow$ T = $\sqrt{\frac{8H}{g}}$ = 2 $\sqrt{\frac{2H}{g}}$