CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A stone is thrown at an angle θ to the horizontal reaches a maximum height H. Then the time of flight of stone will be
  1. 22H sin θg
  2. 2Hg
  3. 22Hg
  4. 2H sin θg


Solution

The correct option is C 22Hg
H=u2sin2θ2g and T=2u sin θgT2=4u2sin2θg2
T2H=8gT=8Hg=22Hg

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image