Question

A stone is thrown up with a speed of 10 m/s. How high will it go before it begins to fall? ($g=9.8m/s^2$)

• A. 51 m
• B. 0.51 m
• C. 510 m
• D. 5.1 m

Answer 1

Answer: (D)

5.1 m

For this problem we have to use the formula : $v^2-u^2=2aS$

Here, $v=0$, at highest point the $velocity$ of stone is $zero$ and

$a=g=9.8,u=10m/s$ and $S=h$

Thus, $0^2-{10}^2=2\left(9.8\right)h$ or $h=5.1m$