CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A stone is thrown upwards with a speed $$u$$ from the top of a tower. It reaches the ground with a velocity $$3u$$. The height of the tower is


A
u2g
loader
B
2u2g
loader
C
3u2g
loader
D
4u2g
loader

Solution

The correct option is D $$\cfrac { { 4u }^{ 2 } }{ g } $$
Initial velocity$$=+u$$
Final velocity $$=-3u$$
acc$$=-g$$
$$h=$$?
$$\quad { v }^{ 2 }={ u }^{ 2 }+2gh\quad $$
$$\quad 9{ u }^{ 2 }={ v }^{ 2 }-2gh$$
$$8{ u }^{ 2 }=-2gh$$
$$h=-\cfrac { 4{ u }^{ 2 } }{ g } $$ (-ve means downward displacement)

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image