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Question

A stone is thrown upwards with a speed '$$u$$' from the top of a tower. It reaches the ground with a velocity '$$3u$$'. Find the height of the tower.


A
3
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B
2u2g
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C
3u2g
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D
4u2g
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Solution

The correct option is D $$\dfrac { 4{ u }^{ 2 } }{ g } $$
$$v^2=u^2+2gh$$
$$h=\dfrac{v^2-u^2}{2g}=\dfrac{9u^2-u^2}{2g}=\dfrac{4u^2}{g}$$

Physics

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