A stone is thrown vertically upward with an initial velocity of $40 m s^{- 1}$ ,Taking g= $10 m s^{- 2}$ , find the maximum height reached by the stone.

100 m

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60 m

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80 m

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120 m

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Solution

The correct option is C $80 m$
$v^{2} = u^{2} + 2 a s$

$0 = 40^{2} + 2 (- 10) s$

$s = \frac{40 \times 40}{2 \times 10}$
$s = 80 m$

Suggest Corrections

Similar questions

40 m s^{- 1}

g = 10 m s^{- 2}

40 m / s

g = 10 m / s^{2}

g = 10 m / s^{2}

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