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Question

A stone is thrown vertically upward with an initial velocity of 40ms1. Taking g=10ms2, the maximum displacement and distance covered by the stone on reaching the ground is

A
Displacement = zero; distance = 80 m
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B
Displacement = zero; distance covered = 160 m
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C
Displacement = 80 m; distance = 160 m
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D
Displacement and distance = 180 m
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Solution

The correct option is B Displacement = zero; distance covered = 160 m
Answer is B.
Given that Initial velocity, u = 40 m/s, Final velocity, v = 0 m/s.
Acceleration due to gravity, g = 10m/s2 (downward motion).
Maximum height, s = H.
As the body is thrown upward a = -g the relation v2=u22as gives v2=u22aH, we have,
H = u2v22g=40m/s2022(10m/s2)=160020=80m.
If a stone is thrown vertically upward, it returns to its initial position after achieving maximum height.
so, the net displacement = Difference of positions between initial and final positions = 0.
Total distance covered = 80 m + 80 m = 160 m.
Hence, the displacement is 0 and the total distance covered is 160 m.

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